5 SOLVED PROBLEMS OF PARABOLA
EXAMPLE#1
Find the focus and the directrix of
The following parbola
y2 = 16x
x = 16y2
4p = 16
4 4
p = 4
Focus = (h+4,0) Directrix: y=k – 4
Focus = (4,0) Directrix: x = -4
GRAPH:
EXAMPLE#2
Find the directrix,focus, and vertex of
The parabola
y = ½ x2
(x – h)2 = 4p(y – k) Standard Form
1/2 x2 = y
x2 = 2y
2 = 4p
4 4
p = ½
(x – 0)2 = 4(1/2)(y – 0)2
Vertex (0,0) Focus (0,1/2) Directrix: y = -1/2
GRAPH:
EXAMPLE#3
Determine the vertex,focus, and the
Directrix of the parbola from this
Equation and graph
(y – 1)2 = 8(x + 5)
Vertex (h,k) = (-5,1)
Focus = 4p = 8
4 4
p = 2 Focus: (-5+2,1)
Focus: (-3,1)
Directrix: x = - 5 - 2
Directrix: x = -7
GRAPH:
EXAMPLE#4
Determine the diractrix , focus and
The vertex of the parabola and graph
(x – 3)2 = 3(y + 1)
Vertex (h,k) = (3,-1)
4p = 3
4 4
Focus (3,-1 + ¾) Focus (3, - ¼)
Directrix: y = 1 – ¾ Directrix: y = -7/4
GRAPH:
EXAMPLE#5
Find the Standard Form of a parabola
from the given directrix and vertex and
graph
Vertex (0,4) Directrix: y = 2
SOLUTION
P = 2
Focus = (0,4+2) Focus (0,6)
(x-h)2 = 4p(y-4)
(x-0)2 = 4(2)(y – 4)
x2 = 8(y – 4)
x2 = 8y – 32
y = 1/8 (x2 + 32) S.F
GRAPH:
And that's all :)
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